Question
To plan a liquid-liquid extraction we need to know the solute's distribution ratio between the two phases. One approach is to carry out the extraction
To plan a liquid-liquid extraction we need to know the solute's distribution ratio between the two phases. One approach is to carry out the extraction on a solution containing a known amount of solute. After extracting the solution, we isolate the organic phase and allow it to evaporate, leaving behind the solute. In one such experiment, 1.235 g of a solute with a molar mass of 117.3 g/mol is dissolved in 10.00 mL of water. After extracting with 5.00 mL of toluene, 0.889 g of the solute is recovered in the organic phase.
(a) What is the solute's distribution ratio between water and toluene?
(b) If we extract 20.00 mL of an aqueous solution containing the solute with 10.00 mL of toluene, what is the extraction efficiency?
(c) How many extractions will we need to recover 99.9% of the solute?
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Elementary Statisitcs
Authors: Barry Monk
2nd edition
1259345297, 978-0077836351, 77836359, 978-1259295911, 1259295915, 978-1259292484, 1259292487, 978-1259345296
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