[Solved] To prove equalities are correct, n 1.001

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To prove equalities are correct, n 1.001 + n log n = Theta(n 1.001 ) 10n 3 + 15n 4 + 100n 2 * 2

To prove equalities are correct,

n^1.001 + n log n = Theta(n^1.001)

10n³ + 15n⁴ + 100n² * 2ⁿ = O(100n² * 2ⁿ)

To prove equalities are incorrect,

n³ * 2ⁿ + 6n² * 3ⁿ = O(n³ * 2ⁿ)

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