Question
To solve these problems, we need to understand the definitions and properties of probabilities for mutually exclusive events. Given: P(A)=0.56P(A) = 0.56P(A)=0.56 P(B)=0.31P(B) = 0.31P(B)=0.31
To solve these problems, we need to understand the definitions and properties of probabilities for mutually exclusive events.
Given:
- P(A)=0.56P(A) = 0.56P(A)=0.56
- P(B)=0.31P(B) = 0.31P(B)=0.31
Since events AAA and BBB are mutually exclusive, they cannot occur simultaneously. Therefore, P(AB)=0P(A \cap B) = 0P(AB)=0.
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Probability and Stochastic Processes A Friendly Introduction for Electrical and Computer Engineers
Authors: Roy D. Yates, David J. Goodman
3rd edition
1118324560, 978-1118324561
