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traditional method to test the real estate agent's claim at the 0.05 level of significance. (hint: using t-distribution) 38. A maker of frozen meals claims

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traditional method to test the real estate agent's claim at the 0.05 level of significance. (hint: using t-distribution) 38. A maker of frozen meals claims that the average caloric content of its meals is 800. A researcher tested 12 meals and found that the average number of calories was 873 and the standard deviation 25. Is there enough evidence to reject the claim at a =0.02? Assume the variable is normally distributed. Use p-value method or traditional method. (hint: using t- distribution) 39. A medical researcher says that less than 25% of U.5. adults are smokers. In a random sample of 200 U.5. adults, 20% say that they are smokers at o = 0.02, is there enough evidence to support the researcher's claim? Use p-value method or traditional method 40. A medical researcher says that more than 35% of U.S. adults are smokers. In a random sample of 100 U.S. adults, 40% say that they are smokers at a = 0.05, is there enough evidence to support the researcher's claim? Use p-value method or traditional method 41. A medical researcher says that 25% of U.5. adults are smokers. In a random sample of 400 U.S. adults, 35% say that they are smokers at a = 0.01, is there enough evidence to support the researcher's claim? Use p-value method or traditional method 42. In an analysis investigation the usefulness of pennies, the cents portions of 80 randomly selected checks are recorded. The sample has a mean of 25.8 cents and standard deviation of 31.0 cents. If the amounts from 0 to 50 cents are all equally likely, the mean is expected to be 45.7 cents. Use a 0.02 significance level to test the claim that the sample is from a population with a mean less than 45.7 cents. Use p-value method or traditional method. (hint: using t- distribution) 43. In an analysis investigation the usefulness of pennies, the cents portions of 80 randomly selected checks are recorded. The sample has a mean of 25.8 cents and standard deviation of 31.0 cents. If the amounts from 0 to 50 cents are all equally likely, the mean is expected to be 45.7 cents. Use a 0.02 significance level to test the claim that the sample is from a population with a mean less than 45.7 cents. Use p-value method or traditional method (hint: using t- distribution)

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