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Transition from Calculus to DiffEq: The Forced Oscillator DiffEq a) Here's a solution to a differential equation: y[t] = e (Kl 5 +K2 6'5)

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Transition from Calculus to DiffEq:

The Forced Oscillator DiffEq

image text in transcribed
a) Here's a solution to a differential equation: y[t] = e\" (Kl 5 \" +K2 6'5\") K1 and K2 are constants set by starter data. This solves the differential equation: 3; "[t] + b y '[t] + e y[t] = 0. What are b and e

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