Translate the following loop into C. Assume that the C-level integer i is held in register $t1, $s2 holds the C-level integer called result, and $s0 holds the base address of the integer MemArray.

addi $St1, $0, 0 addi $s2, $0, 0 addi $s3, $0, 0 LOOP: lw $s1, 0($s0) add $s2, $s2, $s1 addi $s0, $s0, 4 Page 1 of 2 addi $t1, $t1, 1 add $s2, $s2, $s1 add $s2, $s2, $s1 add $s2, $s2, $s1 slti $t2, $t1, 100 bne $t2, $s3, LOOP