Question
TV 4 1 sin5 x dx 0 At first I divided sin5 x dx to sin4 x sin x dx And I changed sin x
TV 4 1 sin5 x dx 0 At first I divided sin5 x dx to sin4 x sin x dx And I changed sin x to 1 cos x in terms of the Cosine function After that I solved it by using integral rules But I couldn t solve it Can anyone give me a hint to solve it I attached my calculations below
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A Course In Differential Geometry
Authors: Mofidul Islam
1st Edition
9353147107, 9789353147105
