Two thin rods of length 49.0 cm are placed side-by-side as shown below, separated by a distance x = 1.40 cm. The positive rod has total charge 5.30 nC. The electric field a distance d = 23.5 cm away from the positive rod is zero. What is the magnitude of the charge on the negative rod? + X + + + + d + + Magnitude of charge (input a positive answer): Submit Answer Tries 0/99Two thin rods of length 49.0 cm are placed sideby-side as shown below, separated by a distance X = 1.40 cm. The positive rod has total charge 5.30 nC. The electric field a distance d = 23.5 cm away from the positive rod is zero. What is the magnitude of the charge on the negative rod? Magnitude of charge (input a positive answer): 5.61 nC Submit Answer You have entered that answer before Tries 5/99 Previous Tries Answer length of the two rod is L = 49.0 cm = 0.4.9m positive rod has a change Q1 = 5.30 nc So , electric field at a distance d= 2:35 cm = 0.235m from The positive wood is Antod ( ( L ) 2 + d2 consider - Q2 is The negative change on the negative wod : so electric field at a distance ( dto from the negative rode F2 = - 4 x to ( d + 20 )