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uestion 19 What is the rate law for the following mechanism: O2 (g) + NO (g) = NO3 (g) (fast equilibrium; rate of forward reaction:

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uestion 19 What is the rate law for the following mechanism: O2 (g) + NO (g) = NO3 (g) (fast equilibrium; rate of forward reaction: k1, rate of reverse reaction: k-1) NO (g) + NO3 (g) N204 (g) (slow, rate: k2) Rate=k2 [NO][NO3] . B. Rate=k2 [02][NO]2 oc Rate= (kj/k_1) [02][NO]2 D. Rate= k2 (kj/k-1) [02] [NO]2 e Rate= (k/k_1)[0212[NO] A Moving to another question will save this response

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