uestion#$3$: Determine the tension in the cables.

${\displaystyle \underset{?}{\overset{?}{}}}fx=0\mathrm{.}5-0\mathrm{.}70=0$

${\displaystyle \underset{?}{\overset{?}{}}}fy=0\mathrm{.}86-0\mathrm{.}70-12\mathrm{.}5=0$

$\frac{B}{sin75}=\frac{{45}^c}{sin45}=\frac{A}{sin60}$

Answers:

$T_{AB}=9\mathrm{.}19$

$T_{BC}=6\mathrm{.}56$