unsigned int oddParitySet$3($unsigned int intArg, unsigned int startBit$)$;

This function will determine the odd parity for a $3-$bit segment of intArg starting at bit startBit and set the parity bit $($low$-$order bit$)$ appropriately.

E$.$g$.,$ suppose intArg$=6$ and startBit $=2.$ The $32$ bit representation, from high to low, would be $29$ zeros then $110.$ So$,$ bits $2-0$ are $110.$ To make the parity odd, you would set bit zero to $1.$

The return value is the modified intArg, in this case it would be $29$ zeros then $111$ or a value of $7.$

Do not convert intArg to a string and operate on that. Use only integers or unsigned integers.

Note: If the start bit is greater than $31$ or less than $2,$ return a zero.

correct the following code accordingly to these directions:

unsigned int oddParitySet$3($unsigned int intArg, unsigned int startBit$)\{$

if $($startBit $<3||$ startBit $>31)\{$

return $0$;

$\}$

unsigned int threeBits $=($intArg $>>($startBit$-1))$ &$0$x$7$;

unsigned int oddParityBit $=0$;

for $($int i $=0$; i $<3$; i$++)\{$

oddParityBit $^=($threeBits $>>$ i$)$ & $0$x$1$;

$\}$

intArg &$=$ ~$(1$u $<<($startBit $-1))$;

intArg $|=($oddParityBit $<<($startBit $-1))$;

return intArg;

$\}$