Question
Show that the convolution y(n)=x(n)*h(n) of the following pairs of signals: x(n) = aru(n), h(n) = bru(n) when a b and when a =
Show that the convolution y(n)=x(n)*h(n) of the following pairs of signals: x(n) = aru(n), h(n) = bru(n) when a b and when a = b It is equivalent to: y (n) = { bn +1 n+1 b a -u(n), bn (n + 1)u(n), Hint: Use the following sum of geometric series: n Sn = rk k=0 1 ph+1 1-r ab a = b
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