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Use a loop invariant to prove that the following algorithm computes a^n: Exp(a, n) { i leftarrow 1 pow leftarrow 1 while (i lessthanorequalto n)
Use a loop invariant to prove that the following algorithm computes a^n: Exp(a, n) { i leftarrow 1 pow leftarrow 1 while (i lessthanorequalto n) { pow leftarrow pow*a i leftarrow i + 1 } return pow }
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