Use Equation $6\mathrm{.}45$ to calculate the molar entropy of krypton at $298\mathrm{.}2K$ and one bar, and compare

Equation $6\mathrm{.}45$: $\frac{?}{\text{b}\text{a}\text{r}}(S)=\frac{5}{2}R+Rln[(\frac{2m{k}_{B}T}{h^2}{)}^{\frac{3}{2}}\frac{(\frac{?}{\text{b}\text{a}\text{r}}(V))g_{e1}}{N_A}]$