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Use integration by substitution to find the indefinite integral in part (a) and to evaluate (to 2 d.p.) the definite integral in part (b).
Use integration by substitution to find the indefinite integral in part (a) and to evaluate (to 2 d.p.) the definite integral in part (b). 3x-2 (a) | da (b) 2x34x L 3 1 e 1 + 1 dt
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