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Use mathematical induction to show that when n is an eaxct power of 2, the solution of the recurrence T(n) = 2 if n =
Use mathematical induction to show that when n is an eaxct power of 2, the solution of the recurrence
T(n) = 2 if n = 2, T(n) = 2T(n/2) + n if n = 2^{k}, for k > 1
is T(n) = n log n
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