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Use mathematical induction to show that when n is an eaxct power of 2, the solution of the recurrence T(n) = 2 if n =

Use mathematical induction to show that when n is an eaxct power of 2, the solution of the recurrence

T(n) = 2 if n = 2, T(n) = 2T(n/2) + n if n = 2^{k}, for k > 1

is T(n) = n log n

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