use matlab

where p is the electrical resistivity measured in ohm-meters 7 is the length of the wire A is the cross-sectional area of the wire This results in the equation for power P=14 Electrical resistivity is a material property that has been tabulated for many materials. For example Material Silver Copper Gold Aluminum Iron Resistivity, ohm-meters (measured at 20C) 1.59 x 10- 1.68 x 10- 2.44 x 10-8 2.82 x 10-8 1.0 x 10-7 Calculate the power that is dissipated through a wire with the following dimensions for each of the materials listed. diameter 0.001 m length 2.00 m Assume the wire carries a current of 120 amps. Make your Resistivity a column vector in this problem. Note that the elements of P should be in the same order as the Resistivity table and Pw Moore Problem 2.15 Script Type here to search akhan - Close Courses MS Integration Documentation ENGR 20 Ticket 66165 > Project 1-1 > Moore Problem 2.16 O solutions submitted (max 3) 2.16 Repeat the previous problem for 10 wire lengths, from 1 m to 1 km. Use logarithmic spacing. (Le repeat Problem 2.15 as described. Make sure that you make the Resistivity a column vector so that will now a 5 x 10 mar. You will need to use element by element multiplication. The rows of P should then be in the same order as the rows in the Resistivity table in Problem 2.15) Moore Problem 2.16 Reset E MATLAB Documentation Script Note that P15 now as X 10 matrix Run Script Submit (Attempt 1 of 3 Run Pretesto Assessment: > Check that P is 5 x 10 (Pretest) P matrix