use python

3. The constant is an irrational number with value approximately 3.1415928 . . . The precise value of is equal to this infinite sum: 4/1- 4/3 +4/5-4/7 + 4/9- 4/11 + . .. sum approxH( ) that takes as input a float-value error and approximates constant within error by computing the preceding sum, term by term, until the difference between the current sum and the previous sum (with one less term) is no greater than error. The function should return the new sum. s>approxPi(0.01) 3.1465677471829556 >>>approxPi(0.0000001) 3.141592703589814