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Use Python to find the target SHA - 2 5 6 hash that starts with one zero by appending a value x to hashBlock 1

Use Python to find the target SHA-256 hash that starts with one zero by appending a value x to hashBlock1 i.e. find x so that SHA-256(hashBlock1, x) starts with a zero
Can somebody help me extend the code I have to add more leading zeros (2,3,4,5). Then tell me what do you notice?
import hashlib
BUF_SIZE =32768
# Step 1
hash_object = hashlib.sha256()
# Replace 'your_file_path.txt' with the actual path to your file
file_path = 'your_file_path.txt'
# Step 2
with open(file_path, 'rb') as f:
while True:
data = f.read(BUF_SIZE)
hash_object.update(data)
if not data:
break
# Step 3
hex_digest = hash_object.hexdigest()
# Step 4
with open('hash.txt','w') as hash_file:
hash_file.write(hex_digest)
# Step 5
with open(file_path, 'a') as modified_file:
modified_file.write("Additional content.")
# Step 6
hash_object = hashlib.sha256()
with open(file_path, 'rb') as f:
while True:
data = f.read(BUF_SIZE)
hash_object.update(data)
if not data:
break
# Step 7
modified_hex_digest = hash_object.hexdigest()
# Step 8
with open('hash.txt','a') as hash_file:
hash_file.write('
'+ modified_hex_digest)
# Step 9
if hex_digest == modified_hex_digest:
print("The hashes are the same.")
else:
print("The hashes are different.")do you notice?

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