Use the chain rule to determine aw aw w=e t= vts, v=rs ar We have dw = aw 2x + away = (vet" ) (1) + (teto) (s) ar ax ar ay ar = Crs (e+s))+ (s (rts) (e*+s)(rs)) = (r se ( r 2 stus ") ) + ( ( sr+ 5 2 ) ( etv + s ) (rs) ) and . aw = aw ax + aw ay = (ve* ) (1)+ (tet ) (s ) d's ax as ay as = (rge( strst) ) (r" +rs ) e(r+s) (rs))