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Use the differential dz to approximate the change in z = V6 - x2 - y as (x, y) moves from (1, -1) to (1.01,

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Use the differential dz to approximate the change in z = V6 - x2 - y as (x, y) moves from (1, -1) to (1.01, -0.97) Az~ What is the actual change in the function? (Round to 5 decimal places)

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