Consider the Archimedian Spiral r = 30 + 5,0 [0, 2] plotted below in black. The tangent to the spiral when 0 = is plotted in blue. T 3 T 4 5 T 4 EN- 35 ST 3 T 2 T 4 Find the point a(T) = The Cartesian equation of the tangent to the curve at a() is y = The Cartesian equation of the normal to the curve at a() is 7 T A parametric form of this spiral can be found by using t=0 as the parameter: a(t) = [(5+3t) cos(t), (5 + 3t) sin(t)] . -0 y = Note: the Maple syntax for [T, 0] is [Pi, 0] and you may find concepts from the previous calculus topics useful here.