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Use the following data to answer the items below: mass of unknown nonelectrolyte = 1 614 g freezing point of pure solvent = 0.05C mass
Use the following data to answer the items below: mass of unknown nonelectrolyte = 1 614 g freezing point of pure solvent = 0.05C mass of solvent (water) = 20.147 g mass of empty test tube = 35.223 g time (min.) 8.0 5.5 6.0 time (min.) 0.0 0.5 1.0 1.5 2.0 2.5 3.5 4.0 temp. (0) 2.25 1.57 1.00 0.46 -0.07 -0.56 -1.42 -1.78 -2.12 temp. (C) -2.43 -2.72 -2.97 -1.71 -1.73 -1.75 -1.80 7.0 TIB Ou 9.0 -1.83 4.5 OS -1.86 Part A Plot the temperature-time data to determine the freezing point of the solution. Be sure to read the lab experiment or you will likely do this incorrectly (and be frustrated)! You'll find the most successful approach involves printing a hard copy of the graph and using a ruler. What is the freezing point of the solution
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