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Use the prime divisor property to show that the proper divisors of 2^(n1)p, for any odd prime p, are 1, 2, 2^2, ..., 2^(n1) and
Use the prime divisor property to show that the proper divisors of 2^(n1)p, for any odd prime p, are 1, 2, 2^2, ..., 2^(n1) and p, 2p, 2^2p,..., 2^(n2)p.
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