USING C++:

Write a function that given a list of numbers as an array of doubles A of size n, will return the number of elements that are larger than the very next element in the array. The function prototype is provided below.

E.g. if A={ 10, 12, 1, 4, 7,-3, 9, 22}, then outOfOrder(A,8) will return 2 (since 12>1 and 7>-3)

int outOfOrder(double[], int);