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using intergral to ' 5. Find the surface area of the surface generated when the curve y = va from (1, 1) to (4,2) revolves

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using intergral to '

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5. Find the surface area of the surface generated when the curve y = va from (1, 1) to (4,2) revolves around the x-axis, as shown below. y = v x 2 y -1 T - 1 -2 Z 1 2 3 2 X

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