Question
Using Matlab: A microorganism is capable of using glucose, methanol, and hexadecane, singly. Its average cell composition (by weight) was analyzed to be 47% carbon,
Using Matlab: A microorganism is capable of using glucose, methanol, and hexadecane, singly. Its average cell composition (by weight) was analyzed to be 47% carbon, 6.5% hydrogen, 31% oxygen, 10% nitrogen, and the rest is ash. During active metabolism, the microorganism converts the substrate, oxygen, and ammonia into biomass, carbon dioxide, and water. A batch culture was carried out to estimate the cell yield based on substrate and oxygen (kg cells/kg substrate or oxygen). Air was supplied continuously and the exhaust gas was vented from the top of the bioreactor. A mass spectrometer was available for gas composition analysis. The water vapor was removed from both inlet and outlet gases before analysis. The inlet gas was ambient air (21% oxygen and 79% nitrogen). The composition of the off-gas on a volumetric basis is listed below. What are the estimated cell yield coefficients based on ammonia and oxygen for the consumption of glucose? Substrate: glucose, percent nitrogen: 78.8%, % carbon dioxide:10.2, % oxygen:11
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