Question
USING PYTHON In addition to searching for occurrences of strings, you can also use Python regular expressions to perform string substitutions. While most word processors
USING PYTHON
In addition to searching for occurrences of strings, you can also use Python regular expressions to perform string substitutions. While most word processors will find and replace identical strings, you can use regular expressions to match similar strings. For example, you have the following strings:
my val
my-val
my_val
my=val
my&val
You really want them all to be myval. Instead of parsing through your information and replacing each individual occurrence, you can use a regular expression to perform the find and replace
The python pattern is
pattern="my[ -_=&]val"
Regular Expression Search Challenge
Using the Python string below to perform a search using a regular expression that you create.
search_string=This is a string to search for a regular expression like regular expression or regular-expression or regular:expression or regular&expression
Write a regular expression that will find all occurrences of: a. regular expression b. regular-expression c. regular:expression d. regular&expression in search_string
Assign the regular expression to a variable named pattern
Using the findall() method from the re package determine if there are occurrences in search_string
Assign the outcome of the findall() method to a variable called match1
If match1 is not None: a. Print to the console the pattern used to perform the match, followed by the word matched
Otherwise: a. Print to the console the pattern used to perform the match, followed by the words did not match
Complete this code:
import re
#Sentence with phrase to replace sentence='In my string, I have my val, my-val, my_val, my&val and my=val. But what I really want is my--val.'
#Pattern with the expression to replace pattern = "my[ -_&=]val"
#String to use for substitution substitution="my--val"
#Print out the original sentence print(sentence + " ")
#Replace the regular expression with the substitution string match = re.findall(pattern, sentence)
#Print out the results of the match print("Match = %s " % str(match))
#Replace the results replace_results = re.sub(pattern, substitution, sentence)
#Print out the string containing the substitutions print(replace_results)
#given search string
search_string="This is a string to search for a regular expression like regular expression or regular-expression or regular:expression or regular&expression"
pattern = "regular[ -:&]expression" #regular expression created
match1 = re.findall(pattern, search_string) #using findall to find all occurences
print(" ---------Regular Expression Search Challenge-------------- ") #header
#if match1 is not none
if match1:
print("Pattern used: %s "%pattern) #print pattern
print("matched ") #print given word 'matched'
print("Words matched: %s "%str(match1)) #print results. you can remove this line
#if match1 is empty
else:
print("Pattern used: %s " %pattern) #print pattern
print("did not match") #print words 'did not match'
regex_replac... X 1 2 3 4 5 6 import re #sentence with phrase to replace sentence-' In my string, I have my val, my-val, my-val, my&val and my-val. But what I r :Pattern with the expression to replace pattern "my [ --&z]val'' = 8 #String to use for substitution 10 substitution "my-val" :Print out the original sentence 12 13 14 15 print (sentence +"n") #Replace the regular expression with the substitution string match re . findall (pattern, sentence) 18 :Print out the results of the match print ("Match %s " % str(match)) 19 21 23 = #Replace the results replace-results re.sub(pattern, substitution, sentence) :Print out the string containing the substitutions print(replace_results) #given search string search_string-"This is a string to search for a regular expression like regular express pattern- "regular[-&] expression" #regular expression created match re. findau (pattern, search-string) #using findall to find all occurences print("nRegular Expression Search Challengen" #if match! is not none 26 27 30 31 34 35 36 37 38 39f matchl: 40 print ("Pattern used : %s "%pattern) #print pattern regex_replac... X 1 2 3 4 5 6 import re #sentence with phrase to replace sentence-' In my string, I have my val, my-val, my-val, my&val and my-val. But what I r :Pattern with the expression to replace pattern "my [ --&z]val'' = 8 #String to use for substitution 10 substitution "my-val" :Print out the original sentence 12 13 14 15 print (sentence +"n") #Replace the regular expression with the substitution string match re . findall (pattern, sentence) 18 :Print out the results of the match print ("Match %s " % str(match)) 19 21 23 = #Replace the results replace-results re.sub(pattern, substitution, sentence) :Print out the string containing the substitutions print(replace_results) #given search string search_string-"This is a string to search for a regular expression like regular express pattern- "regular[-&] expression" #regular expression created match re. findau (pattern, search-string) #using findall to find all occurences print("nRegular Expression Search Challengen" #if match! is not none 26 27 30 31 34 35 36 37 38 39f matchl: 40 print ("Pattern used : %s "%pattern) #print patternStep by Step Solution
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