Using relational algebra.

Find the names of all travel agents who have more than 10 years of experience and find the average years of experience from all the agents.

MariaDB [hw4]> select * from travelagent; +- -------+- --------- --------+ -------- I +- -- | name | years experience | phone ------- Derek 9 1234567890 | Jaime 14 9876543210 | Nathan 18 5056067070 +- -- --- -- - -----+------------+ 3 rows in set (0.001 sec)