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Using the approximation y (t) solve the BVP - y(t + h) 2y(t) + y(t h) h2 = 4y y(0) = 1 y(1) =

 

Using the approximation y" (t) solve the BVP - y(t + h) 2y(t) + y(t h) h2 = 4y y(0) = 1 y(1) = 3 using finite differences where the interval [0, 1] is split into four sub-intervals.

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