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using the file sig_noise from below create a matlab file that has a signal with one distinct frequency and a signal-to-noise of 5 db. Use

using the file sig_noise from below create a matlab file that has a signal with one distinct frequency and a signal-to-noise of 5 db. Use data rate of 10 kHz and time period of 2 seconds.

a) plot the signal

b) show that this signal does in fact have two different distinct frequencies.

c) demonstrate that the signal does have a signal-to-noise of 5 db.

d) repeat a-c but with 35 distinct frequencies and a signal to noise of -2 db

sig_noise

fs = 1000; % Assume a sampling freq of 1 kHz Ts = 1/fs; time = (0:(N-1))*Ts; noise = randn(1,N); % Generate noise and calculate RMS value rms_noise = sqrt(mean(noise.^2)); if length(snr) < length(freqsin) && length(snr) == 1 % Check SNR vector length snr(2:length(freqsin)) = snr(1); %If a scalor, use this value for all freq. elseif length(snr) < length(freqsin) disp('Error: not enough SNR values') waveform_noise = rms_noise; return end % for i = 1:length(freqsin) freq_scale = freqsin(i) * 2 * pi/fs; x = (1:N) * freq_scale; snr_n = 10^(snr(i)/20); % Convert from dB A = snr_n * rms_noise * 1.414; % Determine gain for appropriate SNR if i == 1 component = sin(x) * A; waveform = component; rms_sig(i) = sqrt(mean(waveform.^2)); else component = sin(x) * A; rms_sig(i) = sqrt(mean(component.^2)); waveform = waveform + component; end snr_out(i) = 20 * log10(rms_sig(i)/rms_noise); % Confirm SNR end waveform_noise = waveform + noise;

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