Using the following information and the rules of Hess's Law, find the enthalpy change for the reaction:

$2H_{3}B{O}_3(aq)B_2{O}_3(s)+3H_{2}O(l)$

$H_{3}B{O}_3(aq)HB{O}_2(aq)+H_{2}O(l)H=-0\mathrm{.}02kJ$

$H_2{B}_4{O}_7(s)+H_{2}O(l)4HB{O}_2(aq)H=-11\mathrm{.}3kJ$

$H_2{B}_4{O}_7(s)2B_2{O}_3(s)+H_{2}O(l)H=-17\mathrm{.}3kJ$

$3.$