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Using the mov.w instruction we copy the 1 6 - bit word 0 B 6 1 2 to the address 0 C 2 A 1

Using the mov.w instruction we copy the 16-bit word 0B612 to the address 0C2A1. You do
not need to know any details of the instruction here, all you care is that the word (0B612) is
stored at the given address }{2A}.
Given this information which of the following questions can you answer? What is the answer?
(a) What is the byte that is stored in location 0x1C29?
(b) What is the byte that is stored in location 0C2A1?
(c) What is the byte that is stored in location 0C2B1?
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