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Using the TI-84 Plus calculator, find the area under the standard normal curve that lies between the following z-values. Round the answers to at

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Using the TI-84 Plus calculator, find the area under the standard normal curve that lies between the following z-values. Round the answers to at least four decimal places. Part: 0 / 2 Part 1 of 2 (a) Find the area under the standard normal curve that lies between z = -1.98 and z = 0.52. The area between z = - 1.98 and z = 0.52 is 0.6762 Check your blood pressure: In a recent study, the Centers for Disease Control and Prevention reported that diastolic blood pressures of adult women in the United States are approximately normally distributed with mean 80.6 and standard deviation 9.7. (a) Find the 30th percentile of the blood pressures. (b) Find the third quartile of the blood pressures. Use the TI-84 Plus calculator and round the answers to at least two decimal places. Part: 0 / 2 Part 1 of 2 The 30th percentile of the blood pressures is 75.31. Fish story: According to a report by the U.S. Fish and Wildlife Service, the mean length of six-year-old rainbow trout in the Arolik River in Alaska is 479 millimeters with a standard deviation of 39 millimeters. Assume these lengths are normally distributed. (a) What proportion of six-year-old rainbow trout are less than 444 millimeters long? (b) What proportion of six-year-old rainbow trout are between 374 and 474 millimeters long? (c) Is it unusual for a six-year-old rainbow trout to be less than 415 millimeters long? Round the answers to at least four decimal places. Part 1 of 3 The proportion of six-year-old rainbow trout less than 444 millimeters long is 0.1874 Part 2 of 3 The proportion of six-year-old rainbow trout between 374 and 474 millimeters long is 0.4449 Part: 2/3 Part 3 of 3 It is millimeters long is unusual because the probability of a six-year-old rainbow trout less than 415 > Fish story: According to a report by the U.S. Fish and Wildlife Service, the mean length of six-year-old rainbow trout in the Arolik River in Alaska is 479 millimeters with a standard deviation of 41 millimeters. Assume these lengths are normally distributed. Round the answers to at least two decimal places. st (a) Find the 61 percentile of the lengths. (b) Find the 77th percentile of the lengths. (c) Find the third quartile of the lengths. (d) A size limit is to be put on trout that are caught. What should the size limit be so that 15% of six-year-old trout have lengths shorter than the limit? Part: 0 / 4 Part 1 of 4 st Find the 61 percentile of the lengths. The 61st percentile of the lengths is 489.78 The following figure is a probability density curve that represents the grade point averages (GPA) of the graduating seniors at a large university. Area = 0.70 Area = 0.23 2.4 2.7 3 3.3 3.6 Part 1 of 2 Find the proportion of seniors whose GPA is between 3 and 3.3. The proportion of seniors whose GPA is between 3 and 3.3 is 0.23 Part 2 of 2 What is the probability that a randomly chosen senior will have a GPA greater than 3.3? The probability that a randomly chosen senior will have a GPA greater than 3.3 is 0.70 Find each of the shaded areas under the standard normal curve using a TI-84 Plus calculator. Round the answers to at least four decimal places. Part: 0 / 4 Part 1 of 4 (a) - 1.92 The area of the shaded region is

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