Using your voltammogram from Question 12, calculate E_1/2 value for K₃Fe(CN)₆ (show the calculation below).

\begin{tabular}{llllllllll} \hline 0.60 & 0.40 & 0.20 & 0.00 & -0.20 & -0.40 & -0.60 & -0.80 & -1.00 & -1.20 \end{tabular} \begin{tabular}{llllllllll} \hline 0.60 & 0.40 & 0.20 & 0.00 & -0.20 & -0.40 & -0.60 & -0.80 & -1.00 & -1.20 \end{tabular}