ust44tn.theexpertta.com The Expert TA | Human-like Grading, Automated! The Expert TA | Human-like Grading, Automated! the ExpertTA.com Class Management | Help Student: mwill232@tnstate.edu My Account Log Out Newton's Laws Begin Date: 3/21/2023 12:01:00 AM -- Due Date: 3/28/2023 11:59:00 PM End Date: 3/28/2023 11:59:00 PM (17%) Problem 5: A strong contestant in a winter sporting event held in Canada pulls a block of ice across a frozen lake by applying a force, F , using a rope at an angle 0 above the horizontal, as shown. F us From the choices below, select all of the forces that should appear on the free body diagram of the block of ice. The weight of the block of ice. Grade Summary Deductions 0% The force of static friction between the rubber boots of the strong contestant and the Potential 100% frozen surface of the lake. The weight of the strong contestant. Submissions Attempts remaining: 10 The normal force on the frozen lake due to the block of ice. (0% per attempt) The force of kinetic friction on the block of ice due to the frozen lake. detailed view The force of static friction on the frozen lake due to the block of ice. The force of static friction on the block of ice due to the frozen lake. The applied force, F, due to the tension in the rope. The normal force of the frozen lake acting on the block of ice. The force of kinetic friction on the frozen lake due to the block of ice. Submit Hint I give up! Feedback: 0% deduction per feedback. Hints: 0% deduction per hint. Hints remaining: 1 All content @ 2023 Expert TA, LLC MacBook Air DD 988 O O 6 3 4 O U E R Kust44tn.theexpertta.com ta The Expert TA | Human-like Grading, Automated! @ 1 + ta The Expert TA | Human-like Grading, Automated! theExpertTA.com Class Management | Help Student: mwill232@tnstate.edu My Account Log Out Newton's Laws Begin Date: 3/21/2023 12:01:00 AM -- Due Date: 3/28/2023 11:59:00 PM End Date: 3/28/2023 11:59:00 PM (17%) Problem 3: When the moon is directly overhead at sunset, the gravitational force on the Moon due to the Earth, FEM , is perpendicular to the gravitational force on the Moon due to the Sun, FSM. These two forces have magnitudes FEM = 1.98 X 1020 N and FSM = 4.36 X 1020 N. Assume that all other forces are negligible. The mass of the Moon is m = 7.35 x 1022 kg. Status FGM for ew atus Moon 4 50% Part (a) Write an expression for the magnitude of the acceleration of the Moon. a = 1 Grade Summary Deductions 0% Potential 100% Y ( ) 7 8 9 Submissions b d FEM 4 5 6 Attempts remaining: 10 (0% per attempt) FSM g h 1 2 3 detailed view K m + - 0 n P S vol Submit Hint I give up! Hints: 0% deduction per hint. Hints remaining: 1 Feedback: 0% deduction per feedback. 4 50% Part (b) What is the acceleration of the Moon in m/s? All content 2023 Expert TA, LLC MacBook Air DD F 10 F12 20 968 F9 F7 F3 F4 F6 Vo 6 4 5 O P Y U E R T G H K