Usually in IR spectroscopy, it is advantageous to run a compound, neat or without the presence of a solvent. Why would using methanol (a common organic solvent] be problematic in IR? (Select ail that apply) A peak will appear around 3400cm1, which are not that of the compound intended to be measured A peak will appear around 3000cm1, which are not that of the compound intended to be measured A peak will appear around 1700cm1, which are not that of the compound intended to be measured Methanol wil contribute to more backeround noise Peaks will appear around 2700 and 2800cm1, which are not that of the cormpound intended to be measured