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' V '7' ' ' W V W E myopenmathcom O ' .Question10 'H' 80/1pt'020 81 The results of a common standardized test
' V '7' " ' ' W " V W" E myopenmathcom O\\ ' .Question10 'H' 80/1pt'020 81 The results of a common standardized test used in psychology research is designed so that the population mean is 120 and the standard deviation is 10. A subject earns a score of 152. What is the z-score for this raw score? Do not round your answer. Question Help: E] Video @ Written Example 8 Message instructor Submit Question Jump to Answer I -, ,, ,7 , ,,,,,, ,, myopenmathcom O ' .Question11 vH , Adult men have heights with a mean of 69.0 inches and a standard deviation of 2.8 inches. Find the height of a man with a z-score of 3.8 (to 2 decimal places) :1 Question Help: El Video @ Written Example 8 Message instructor Submit Question Jump to Answer 80/1 pt '020 2 myopenmath.com The Acme Company manufactures widgets. The distribution of widget weights is bell-shaped. The widget weights have a mean of 43 ounces and a standard deviation of 4 ounces. Use the Standard Deviation Rule, also known as the Empirical Rule (see image below). Do not use normalcdf on your calculator. Suggestion: sketch the distribution in order to answer these questions. a) 68% of the widget weights lie between I and ' I b) What percentage of the widget weights lie between 31 and 47 ounces? :] 96 c) What percentage of the widget weights lie below 51 ? [: 96 Question Help: El Video |% Written Example 8 Message instructor Jumpmnswer myopenmath.com C Question 13 0/3 pts ' 20 99 0 Details The time to complete an exam is approximately Normal with a mean of 42 minutes and a standard deviation of 6 minutes. The bell curve below represents the distribution for testing times. The scale on the horizontal axis is equal to the standard deviation. Fill in the indicated boxes. U = 42 0 = 6 H- 30 1-20 H- 0 H + 20 u+ 30 10 Question Help: B Written Example Message instructor Submit Question Jump to Answer0 Question 14 v l H myopenmathcom C l l lili- 3 0/4 pts '0 20 3 99 (D Details Suppose that the duration of a particular type of criminal trial is known to be normally distributed with a mean of 15 days and a standard deviation of 5 days. Let X be the number of days for a randomly selected trial. Round all answers to 4 decimal places where possible. a. What is the distribution of X? X ~ N(:],[:]) b. If one of the trials is randomly chosen, find the probability that it lasted at least 13 days. C] c. If one of the trials is randomly chosen, find the probability that it lasted between 17 and 20 days. [3 Question Help: Q Written Example Message instructor 7 7 ? , E] " ' '*""*"~\"-\""~ , n W ,, myopenmathcom O ' , - . , , , fl] 7/ 0 Question 15 v I l I 30/3 pts 020 299 Goetails The mean amount of time it takes a kidney stone to pass is 13 days and the standard deviation is 4 days. Suppose that one individual is randomly chosen. Let X = time to pass the kidney stone. a. What is the distribution of X? X ~ N(:],[:) b. Find the probability that a randomly selected person with a kidney stone will take longer than 14 days to pass it. Round to 4 decimal places. [:] Question Help: Q Written Example 8 Message instructor
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