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V Due date: 12:30 PM 11/1/2016 1. A major newspaper is considering to launch an online edition. The newspaper plans to go ahead only if

V Due date: 12:30 PM 11/1/2016 1. A major newspaper is considering to launch an online edition. The newspaper plans to go ahead only if at least 30% of current readers would subscribe. The newspaper surveyed a random sample of 400 current readers, and 130 of those express interest. a. What should the newspaper do? Use appropriate test and state the assumption(s). b. What is the P-value for the test you have conducted in part a? 2. A company that produces cell phone batteries claims their new battery last more than 30 hours. To investigate this claim a consumer advocacy group collected the following random sample for number hours that each battery worked: 50, 40, 35, 25, 60, 55, 30, 50, 30, 20. Is there a sufficient evidence to accept the company's claims using 0.01 significance level? 3. Use MINITAB The main access road to a suburban shopping mall sometimes becomes severely congested. On weekdays, excluding holidays, the average number of vehicles going toward the mall between 9 A.M. and 7 P.M. that pass a counter is 13,260. The highway department tried to improve traffic flow by changing stoplight cycles and improving turn lanes. For the first seven non holiday weekdays after the changes, the volumes were 10,690, 11,452, 12,316, 12,297, 13,089, 11,995, and 12,647. A local politician who reviewed the sample results said that the data proved there had been no improvement in traffic volume. Using a 0.05 significance level Do you think is there a sufficient evidence to accept the politician's interpretation? 4. The average age of online consumers a few years ago was 23.3 years with a standard deviation of 5.3 years. It is believed the average has changed since older individuals gained more confidence with internet use. Recently a random sample of 40 online shoppers were selected. The sample had an average age of 25.2. Determine whether or not the average age of online consumers has changed over the last few years, use =0.01. What is the p-value of the result

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