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variable with Mean = 5000 and =800. Let X * if of weekly customers. (X is Normal RV ) a) Find probabily that number of

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variable with Mean = 5000 and =800. Let X * if of weekly customers. (X is Normal RV ) a) Find probabily that number of customets next week will be between 4760 and 5800 . b) Find probability that number of customers next week will exced 6500 . That is Find Pr(X6500} c) For 90% of the time, the number of customers visiting should exceed what number? Need to find X given that =5000,=800 Interpnetation

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