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Verify that y = -7t cos(t) - 7t is a solution of the following initial-value problem. = y + 7+2 sin(t) y (IT) = 0
Verify that y = -7t cos(t) - 7t is a solution of the following initial-value problem. = y + 7+2 sin(t) y (IT) = 0 dt y = -7t cos(t) - 7t = dy = dt LHS = t- dy = = 7+2 sin(t) - 7t cos(t) - 7t dt = + y = RHS, so y is a solution of the differential equation. Also y(n) = , so the initial condition is satisfied
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