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Wayne Merritt drives from Cleveland to Chicago frequently and has noticed that traffic and weather make a big difference in the time it takes to
Wayne Merritt drives from Cleveland to Chicago frequently and has noticed that traffic and weather make a big difference in the time it takes to make the trip. As a result, he has a hard time planning activities around his arrival time. To better plan his business, Wayne wants to calculate his average driving time as well as a measure of how much an actual trip is likely to vary from that average. To do that, he clocked 10 trips with the results in table.
Driving Time | Number of trips |
6 hrs, 0 min | 1 |
6 hrs, 15 min | 1 |
6 hrs, 33 min | 2 |
6 hrs, 47 min | 3 |
7 hrs, 3 min | 1 |
7 hrs, 30 min | 1 |
9 hrs, 20 min | 1 |
- Calculate the mean, standard deviation, and coefficient of variation of Wayne's driving time to Chicago. (Hint: Treat the 10 trips as the 10 possible outcomes of a discrete probability distribution, each of which has a probability of 0.1.) Do not round intermediate calculations. Round the answers to two decimal places.
Mean fill in the blank 1 minutes Standard deviation fill in the blank 2 minutes Coefficient of variation fill in the blank 3 - Calculate the average variation in driving time. Round the answer to two decimal places. (Hint: the average variation is calculated using the formula .) fill in the blank 4 minutes
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