We are asking you to design an electronic flash that produces maximum luminous intensity but minimizes the length of the discharge, to achieve the current standard of less than 1/1000 of a second. You will need the following materials UNOMAT MTR A source of electric voltage that can provide a maximum electrical potential difference of 100 volts. Figure 1: Electronic camera flash, 2005 model 4 capacitors with a capacity of 200 uF, to the terminals of which a maximum electrical potential 0 If the electrical potential difference applied to the capacitor terminals is higher than 120 volts, the electric field may attain the value of the disruptive electric field of the dielectric between the two surfaces of the capacitor. If this occurs, the dielectric will become a conductor; an intense electric current will travel between its walls, leaving nothing but a useless, burnt-out capacitor. An incandescent electric bulb with a resistance of 16 ohms. You need a maximum power of 2500 watts at the bulb terminals for it to light with optimal intensity without burning out. If the power supplied to the bulb is higher than this limit, the bulb will likely burn out and stop working You need a minimum power of 1300 watts at the bulb terminals for it to light properly. Below this power, the bulb will not emit enough light for the requirements of the flash. 1) What configuration will you use to charge your system from the source of voltage, to maximize the energy stored each capacitor? Calculate the total energy stored in the chosen circuit. a. What parameters influence the energy stored in a capacitor? b. How is the voltage at the terminals of each capacitor affected by the choice of a series, mixed or parallel charge circuit? 2) Assuming that the capacitors have been charged by the circuit selected in question 1, you must now configure the discharge circuit. What discharge circuit configuration uses the fewest capacitors while still allowing the system to be functional without burning out the capacitors? a How does limiting the power of the electric bulb affect the quantity of capacitors required in the circuit b. What physical parameters do you have to limit to avoid burning out a capacitor when mounting the discharge circuit? 3) What configuration will you use to discharge your system into the bulb, knowing that the flash will have to release as much energy as possible without exceeding the maximum power of the bulb and without exceeding a duration of 1/1000 of a second? a What do you need to maximize in the discharge circuit if you want to maximize the energy in the flash? b What equation describes the graph of the power consumed by the electric bulb as a function of time in an RC circuit? c. Without exceeding the discharge time of 1/1000 of a second, how does a given configuration of capacitors maximize the energy dissipated by the flash? In this case what will be the duration of the flash? We are asking you to design an electronic flash that produces maximum luminous intensity but minimizes the length of the discharge, to achieve the current standard of less than 1/1000 of a second. You will need the following materials UNOMAT MTR A source of electric voltage that can provide a maximum electrical potential difference of 100 volts. Figure 1: Electronic camera flash, 2005 model 4 capacitors with a capacity of 200 uF, to the terminals of which a maximum electrical potential 0 If the electrical potential difference applied to the capacitor terminals is higher than 120 volts, the electric field may attain the value of the disruptive electric field of the dielectric between the two surfaces of the capacitor. If this occurs, the dielectric will become a conductor; an intense electric current will travel between its walls, leaving nothing but a useless, burnt-out capacitor. An incandescent electric bulb with a resistance of 16 ohms. You need a maximum power of 2500 watts at the bulb terminals for it to light with optimal intensity without burning out. If the power supplied to the bulb is higher than this limit, the bulb will likely burn out and stop working You need a minimum power of 1300 watts at the bulb terminals for it to light properly. Below this power, the bulb will not emit enough light for the requirements of the flash. 1) What configuration will you use to charge your system from the source of voltage, to maximize the energy stored each capacitor? Calculate the total energy stored in the chosen circuit. a. What parameters influence the energy stored in a capacitor? b. How is the voltage at the terminals of each capacitor affected by the choice of a series, mixed or parallel charge circuit? 2) Assuming that the capacitors have been charged by the circuit selected in question 1, you must now configure the discharge circuit. What discharge circuit configuration uses the fewest capacitors while still allowing the system to be functional without burning out the capacitors? a How does limiting the power of the electric bulb affect the quantity of capacitors required in the circuit b. What physical parameters do you have to limit to avoid burning out a capacitor when mounting the discharge circuit? 3) What configuration will you use to discharge your system into the bulb, knowing that the flash will have to release as much energy as possible without exceeding the maximum power of the bulb and without exceeding a duration of 1/1000 of a second? a What do you need to maximize in the discharge circuit if you want to maximize the energy in the flash? b What equation describes the graph of the power consumed by the electric bulb as a function of time in an RC circuit? c. Without exceeding the discharge time of 1/1000 of a second, how does a given configuration of capacitors maximize the energy dissipated by the flash? In this case what will be the duration of the flash
