We can find the solutions of sin(x) = 0.33 algebraically. ; (a) First we find the solutions in the interval [0, 2x). We get one such solution by t 'to get x = X (smaller value rounded to two decimal places). The other solution in this interval is x = [: X (larger value rounded to two decimal places). (b) We find all solutions by adding multiples of to the solutions in [0, 27). The solutions are x = , 9 . (Enter your answers in the form v 0 + 27k, 0