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We consider the tube of equation C = {(x, y, z)|x 2 + y 2 = 1, 0 z 1}, oriented with a normal vector

We consider the tube of equation

C = {(x, y, z)|x 2 + y 2 = 1, 0 z 1}, oriented with a normal vector pointing inwards (i.e. towards the z axis). We consider the field of vectors

F(x, y, z) =x3ez+2xy+zcos(y2)y3ez+sin(xez)y20

Use the Gaussian divergence theorem to compute

CFdS

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