We have been ignoring the fact that the meter stick has mass and that gravity is putting a force on it as well. The reason is because these meter sticks are ideal in that their center of mass is in the middle of the meterstick at 50cm. When the pivot point is at the 50 cm mark, the torque that the mass puts on the meterstick is zero. Let's move the pivot and see what happens. In this situation, the center of mass of the meter stick is at the center at 50cm. When a 10 g mass is placed at the 10cm mark, the stick balances when the fulcrum is at 45 cm. What is the mass of the meter stick?