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We have found the following integral for the surface area. S = 2n (x ) V 1 + 9x# dx Jo To evaluate the integral
We have found the following integral for the surface area. S = 2n (x ) V 1 + 9x# dx Jo To evaluate the integral we will first make the substitution u = 1 + 9x#. We also will need the following to complete the substitution. du = 36x3 dx X = 0-U= X = 4- U =
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