Question: We say an integer n is resolute if 3 evenly divides n2 + 2n. (a) Are all odd integers resolute? Either prove that they

We say an integer n is "resolute" if 3 evenly divides n2 

We say an integer n is "resolute" if 3 evenly divides n2 + 2n. (a) Are all odd integers resolute? Either prove that they are or provide a counter-example to show they are not. (b) Prove by contradiction that if n = 3j + 2 for some integer j, then n is not resolute.

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