We want to compute the integral / (2x2 + 4x + 6) edx using two (and only two) integration by parts. This means that you have to make a good choice of f and g' for your two integration by parts. For the first intagration by parts, you should choose [f(z), g'(z)] = [2*x"(2)+4*x+6,e^(4*x)] Warning: for this question, you must use strict calculator notations and also include the square brackets in your answer, in particular, you must use * for every multipliaction (e.g. 2x is written 2*x.) to get (22 2 + 42 + 6) e47 dz = G(z) - H(z)dz, where G(E) = and H() = Now, to integrate H (x) dx, we need to use the method of integration by parts a second time with [f (z),g (z)] = Warning: for this question, you must use strict calculator notations and also include the square brackets in your answer, in particular, you must use * for every multipliaction (e.g. 2x is written 2*x.) to get H(z)dr = BE +C (Don't add the constant of integration C since we have done it for you.) We have then found that (212 + 4x + 6) e4 da =