We wish to absorb ammonia from an air stream using water at 0C and a total pressure of 1.30 atm. The entering water stream is pure water. The entering vapor is 17.2 wt % ammonia. We desire to recover 98% of the ammonia in the water outlet stream. The total gas flow rate is 1050 kg/h. We want to use a solvent rate that is 1.5 times the minimum solvent rate. Assume that temperature is constant at 0C, water is nonvolatile, and air does not dissolve in water. Equilibrium data are available in Table 12-3. Find Lmin , L, and N.

Note: I know the solution is on the book, what I don't understand is, where do you get the 0.477. How did you calculate that number? Also the explain the mass balance, why you divide by 17?. The curvy line comes from the x and y, why the book solution its not that accurate with the numbers? Please, God bless you

M.B.17+GmolYmol=17kmolNH3kgNH+KYout,Ymole=17GmoleLwtXwt+Yout Note: Units, although mixed, work in Mass Balance & in Operating equation. See graph. Minimum Solvent Slope=0.47700.35430.007087=0.7279=17GmoleLwt,minLwt,min=.72791729.98=370.99kgW/hActualSolvent,Lwt=1.5Lmin=556.48hkgWOpLineSlope=17GmoleLwt=1729.98556.48=1.092